All the Writer approaches below rely on this class, either explicitly or under the hood. This class is meant for writing streams of raw bytes.
Files.newBufferedWriter() – Makes it easy to write large filesīelow are details of each.Files.write() – Create and write to a file in a single call.FileWriter – Optional append constructor argument.OutputStreamWriter - The most basic way before Java 5.│ Files.newBufferedWriter() │ Y │ Y │ Y │ │ FileWriter │ Wrap in BufferedWriter │ │ Y │ │ OutputStreamWriter │ Wrap in BufferedWriter │ Y │ Y │ │ │ large files? │ encoding? │ IOException? │
JAVA NEW FILE PROFESSIONAL
This answer is centred on Java 8, and tries to cover all the details needed for the Java Professional Exam. Each has its benefits, and each might be simplest in a given scenario. There are many ways of writing to a file. StandardOpenOption.CREATE, StandardOpenOption.APPEND) įiles.write(Paths.get("file3.txt"), "content".getBytes()) įiles.write(Paths.get("file4.txt"), "content".getBytes(utf8)) įiles.write(Paths.get("file5.txt"), lines, utf8) įiles.write(Paths.get("file6.txt"), lines, utf8, List lines = Arrays.asList("1st line", "2nd line") įiles.write(Paths.get("file1.bin"), data) įiles.write(Paths.get("file2.bin"), data, The following example creates and writes to 6 different files to showcase how it can be used: Charset utf8 = StandardCharsets.UTF_8 If you already have the content you want to write to the file (and not generated on the fly), the addition in Java 7 as part of native I/O provides the simplest and most efficient way to achieve your goals.īasically creating and writing to a file is one line only, moreover one simple method call! Files.write(file, data, StandardOpenOption.APPEND) Files.write(file, lines, StandardCharsets.UTF_8, StandardOpenOption.APPEND) Path file = Paths.get("the-file-name.txt") įiles.write(file, lines, StandardCharsets.UTF_8) Java 7+ users can use the Files class to write to files:Ĭreating a text file: List lines = Arrays.asList("The first line", "The second line") įileOutputStream out = new FileOutputStream("the-file-name")
JAVA NEW FILE CODE
Note that each of the code samples below will overwrite the file if it already existsĬreating a text file: PrintWriter writer = new PrintWriter("the-file-name.txt", "UTF-8") Ĭreating a binary file: byte data =. See this tutorial for information about exception handling. Try/catch/finally blocks have been omitted for brevity. * Creates new file.Note that each of the code samples below may throw IOException. Private static final DateFormat dateFormat = new SimpleDateFormat(pattern) Private static final String pattern = "-dd_M_yyyy-hh_mm_ss."
So here I would use StringBuilder or String.format or something like that.īelow is what I have done in few minutes. Return name + dateFormat.format(new Date()) + ext I dont like spaggetti code when some string is creating like (with +): I also removed return false for InterruptedException - I would like to get another draft of the name in the next iteration. I would remove String getFileName and String getFileExtention and create self-described function and delete in code comments. I will use FilenameUtils for easy manipulation with files like getting basename or extension of file - it will save you some of the lines and also it is one of the most used library for file manipulation. I have not tested it too much but it should works. In my opinion your code it's not so bulky but I would do something like below with few changes. public class FileBackup // never should be here The file name should be human-readable, so I can use neither UUID nor createTempFile. If a file with the given name already exists, it should be renamed by addition of the timestamp to the file name. I have to develop a class that creates new files.
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